well you'll have to wait for your female agouti to have grandbabies to see (only if you are lucky) grey agouti's. Because grey agouti's have black eyes, P* and ruby eyed gerbils carry full recessives for ruby eyes and cannot produce black eyed pups when mated with another ruby eyed gerbil. Like this: Pp X Pp (black eyed parents that both carry the gene for ruby eyes)=PP, Pp, pP and pp (each gene seperates from the other one from the same parent and pairs up with both types of gene from the other parent).
pp x pp = all pp! The pups are all ruby eyed. If one of the parents carried Pp, then the parent would be black eyed because P is dominant and always produces black eyes.
I'm sorry it is so hard to understand. Try writing Pp and Pp on two seperate cards. That represents two black eyed parents that each carry a recessive gene for ruby eyes. Each gerbil parent can contribute only ONE letter to each pup and it is a coin toss to see which gene the baby gets. So cut the cards in half so each half carries a single letter. Then turn the cards over. Pick one letter randomly from the cut cards of each parent. There is a fifty-fifty chance that you will get P or p. Any pup getting P will have black eyes, either like this, PP or like this, Pp. And all pups that get pp will have ruby eyes. So all ruby eyed parents means all ruby eyed pups.
The same goes for all recessive genes. aa x aa parents means all aa pups, and so on, for each of the recessive types: aa, cc, dd, ee, gg, pp. Parents with full recessives can only have recessive pups. So if you want the kind of variety that will give you all the colour types, you have to make sure that there is at least one dominant gene present between the parents that carry lots of recessives. Like this: Aa x aa, or Pp x Pp. Otherwise your pups will be limited to only the fully recessive colours.
Say for example, look at two gene pairs, A and P. A is white belly, aa is self. P is black eyed, pp is ruby eyed. Assume all other genes are wild type (dominant).
An agouti (including grey agouti and colourpoint agouti) is A* P*, both sets dominant genes.
Black is aa P*, recessive a combined with dominant P.
Argente, white bellied with a ruby eye is A* pp, the A is dominant and the p is recessive.
Lilac, self (same colour all over and no white belly) with ruby eyes is aa pp, fully recessive.
Your dark ruby eyed parent gerbs are pp so all the pups are pp, ruby eyed. No black eyed pups can result from this pairing.
So what are the possible coat colour/eye colour genetics of your pair? Well, we know that there are lots ofrecessives.
Parents and pups are all ruby eyed. Dark ruby, but still ruby, so pp for everyone.
Lilac/Dove pups means that both parents carry at least one, if not two a recessives but a dominant gene for each of the other colours. So now we have a* C* D* E* G* pp.
The dove pup means you have at least one c recessive in the parents, so one or both of them is a* Cc(h) pp.
REW pups carry aa gg pp, so now we know each parent carries a g recessive.
To summarize, both parents must be pp and carry one a and one g at least. There has to be a c(h) recessive present.
One parent at least must be dominant in C, D, G and E since the presence of a lilac and dove gerbil shows that there is a dominant in all these genes.
So here's a possible scenario:
Winter could be an unusually light dove with g, as follows: aa Cc(h) DD EE Gg pp
Solace could be a spotted light cream: Aa Cc(h) DD EE gg pp Spsp.
Pop that into your online genetic calculator, and see what comes up:
gerbils.silvanon.com/gerbilcalculator/You can see that with this gene combo there should be some argente and cream pups, eventually, if you keep breeding them. If you don't ever see any, then perhaps there is no A dominant gene present and both parents are aa. In that case, you will get pups that are:
REW
PEW
Dove
Lilac.